Comments on: Finding Thevenin’s Equivalent http://engineersphere.com/basic-electrical-concepts/thevenin-equivalent.html doesn't have to make sense to you, but it's probably great for your health. Tue, 13 Dec 2011 07:30:06 +0000 hourly 1 http://wordpress.org/?v=3.3 By: Jeff http://engineersphere.com/basic-electrical-concepts/thevenin-equivalent.html/comment-page-1#comment-30 Jeff Mon, 04 Oct 2010 20:53:35 +0000 http://engineersphere.com/?p=662#comment-30 If you have a small resistor (approx. 0) in parallel with a current source and then do a source transformation on that current source to model it as a voltage source in series with this resistor (approx. 0), you will have the small supply resistance you're looking for. HOWEVER, when performing source transformations, you multiply this resistance (approx. 0) by the current from the current source to get I(source) x 0 = V(source) = approx. 0. I don't see this working too well. Hope this helped. If you have a small resistor (approx. 0) in parallel with a current source and then do a source transformation on that current source to model it as a voltage source in series with this resistor (approx. 0), you will have the small supply resistance you’re looking for. HOWEVER, when performing source transformations, you multiply this resistance (approx. 0) by the current from the current source to get I(source) x 0 = V(source) = approx. 0. I don’t see this working too well. Hope this helped.

]]> By: rrhodes http://engineersphere.com/basic-electrical-concepts/thevenin-equivalent.html/comment-page-1#comment-29 rrhodes Mon, 04 Oct 2010 20:36:46 +0000 http://engineersphere.com/?p=662#comment-29 Hello, According to Thevenin, a current source in parallel with a short should be equivalent to a voltage source. If I connect a very small valued resistor across a real current source, would I be able to produce a practical voltage source? I am trying to convert a solar cell( modeled as a current source and some other components) into a working voltage source as I need a voltage source for a boost converter. Hello,

According to Thevenin, a current source in parallel with a short should be equivalent to a voltage source. If I connect a very small valued resistor across a real current source, would I be able to produce a practical voltage source? I am trying to convert a solar cell( modeled as a current source and some other components) into a working voltage source as I need a voltage source for a boost converter.

]]> By: Jeff http://engineersphere.com/basic-electrical-concepts/thevenin-equivalent.html/comment-page-1#comment-22 Jeff Tue, 14 Sep 2010 00:56:56 +0000 http://engineersphere.com/?p=662#comment-22 Hi Rayman2o, Thanks for the question. I just reworked the problem and it came out to Vth = 2 V and Rth = 5.98 k. Be aware of the source polarity when doing your initial combination of the voltage source and the 3k resistor. Remember to first short your current source and open your voltage source, then combine all resistors to calculate your Rth. Then, use a series of Norton and Thevenin voltage and current source combinations to calculate your Vth. Good luck! Hi Rayman2o,

Thanks for the question. I just reworked the problem and it came out to Vth = 2 V and Rth = 5.98 k. Be aware of the source polarity when doing your initial combination of the voltage source and the 3k resistor. Remember to first short your current source and open your voltage source, then combine all resistors to calculate your Rth. Then, use a series of Norton and Thevenin voltage and current source combinations to calculate your Vth.

Good luck!

]]> By: rayman2o http://engineersphere.com/basic-electrical-concepts/thevenin-equivalent.html/comment-page-1#comment-21 rayman2o Thu, 09 Sep 2010 08:33:03 +0000 http://engineersphere.com/?p=662#comment-21 how did you get 2v as vth shouldnt it be 3v? thanks how did you get 2v as vth shouldnt it be 3v? thanks

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